|

3 Responses to “How much ice (in grams) would have to melt to lower the temperature of 353 mL of water from 26 C to 6 C?”

1. NC4TC on April 7th, 2010 at 9:49 am

   energy to lower temp of 353ml H2O from 26degC to 6degC

   E = 353ml*1.0g/ml * 1cal/gdegC * 26degC-6degC = 7060calories

   so how many grams of ice will be melted by 7060calories
   it costs 80 cal/g to melt ice
   E=grams ice * 80cal/g grams ice = E/80 cal/g ……. g ice = 7060cal/80cal/g = 88.3 grams ice
   References :

2. biire2u on April 7th, 2010 at 10:29 am

   353 ml of water = 353 g
   26 -6 = 20 C drop needed
   20 * 353g = -7,060 calories needed to be removed with ice

   Ice heat of fusion = 79.7 cal/ gram
   7060 / 79.7 = 88.6 grams of ice needed
   References :

3. drgonzonm on April 7th, 2010 at 10:34 am

   I will not provide the answer. But this question deals with the latent heat of melting and heat capacities. . So you will need the latent heat of melting for water in the proper units. You will also need the heat capacity for water, and possibly ice. Your units It might be in joules, BTU’s, or calories. (Wait a minute, isn’t BTU’s a non SI unit)

   You will need to state an assumption on the temperature of ice. For these calcs use 273 K or 32 F.

   For these calculations, assume your ice is at 273 K. (You may have to take into account
   that you are heating the ice to get it to the temperature that you will melt the ice at). (If you
   assume that the ice is really cold, then you might have to account for the heat of
   crystallization, the above assumption eliminates this correction)

   Then you need to account for heating the water just melted. from 273 K to 6 C. The source below provides the following information Latent heat of melting – 334 kJ/kg

   As just discussed, this problem is not that straight forward. It may take a few iterations to get the correct answer.

   If you want to make the problem easier, lower the temperature of your ice, so it covers the heat capacity ice. other data Specific heat capacity water – 4.187 kJ/kgK; Specific heat capacity ice – 2.108 kJ/kgK

   Good luck.
   References :
   engineeringtoolbox.com/water-thermal-properties-d_162.html

Leave a Reply