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	<title>Comments on: What is the magnitude of the centripetal acceleration of the car?</title>
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	<link>http://www.busireland.net/353/what-is-the-magnitude-of-the-centripetal-acceleration-of-the-car</link>
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		<title>By: Swen</title>
		<link>http://www.busireland.net/353/what-is-the-magnitude-of-the-centripetal-acceleration-of-the-car/comment-page-1#comment-7512</link>
		<dc:creator>Swen</dc:creator>
		<pubDate>Tue, 27 Oct 2009 14:38:59 +0000</pubDate>
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		<description>Yeah, the car simply go around the track. Going the track&#039;s just a law of nature&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>Yeah, the car simply go around the track. Going the track&#8217;s just a law of nature<br /><b>References : </b></p>
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		<title>By: kuiperbelt2003</title>
		<link>http://www.busireland.net/353/what-is-the-magnitude-of-the-centripetal-acceleration-of-the-car/comment-page-1#comment-7511</link>
		<dc:creator>kuiperbelt2003</dc:creator>
		<pubDate>Tue, 27 Oct 2009 13:54:59 +0000</pubDate>
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		<description>a = v^2/r

vel = distance traveled/time

distance = 2 pi r = 2 pi x 3740 m = 23,487.2m

vel = 23487.2/353s=66.5m/s

a=66.5^2/3740m = 1.18m/s/s&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>a = v^2/r</p>
<p>vel = distance traveled/time</p>
<p>distance = 2 pi r = 2 pi x 3740 m = 23,487.2m</p>
<p>vel = 23487.2/353s=66.5m/s</p>
<p>a=66.5^2/3740m = 1.18m/s/s<br /><b>References : </b></p>
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